3.56 \(\int \frac {1}{x (b x^2)^{5/2}} \, dx\)

Optimal. Leaf size=19 \[ -\frac {1}{5 b^2 x^4 \sqrt {b x^2}} \]

[Out]

-1/5/b^2/x^4/(b*x^2)^(1/2)

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Rubi [A]  time = 0.00, antiderivative size = 19, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.154, Rules used = {15, 30} \[ -\frac {1}{5 b^2 x^4 \sqrt {b x^2}} \]

Antiderivative was successfully verified.

[In]

Int[1/(x*(b*x^2)^(5/2)),x]

[Out]

-1/(5*b^2*x^4*Sqrt[b*x^2])

Rule 15

Int[(u_.)*((a_.)*(x_)^(n_))^(m_), x_Symbol] :> Dist[(a^IntPart[m]*(a*x^n)^FracPart[m])/x^(n*FracPart[m]), Int[
u*x^(m*n), x], x] /; FreeQ[{a, m, n}, x] &&  !IntegerQ[m]

Rule 30

Int[(x_)^(m_.), x_Symbol] :> Simp[x^(m + 1)/(m + 1), x] /; FreeQ[m, x] && NeQ[m, -1]

Rubi steps

\begin {align*} \int \frac {1}{x \left (b x^2\right )^{5/2}} \, dx &=\frac {x \int \frac {1}{x^6} \, dx}{b^2 \sqrt {b x^2}}\\ &=-\frac {1}{5 b^2 x^4 \sqrt {b x^2}}\\ \end {align*}

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Mathematica [A]  time = 0.00, size = 17, normalized size = 0.89 \[ -\frac {b x^2}{5 \left (b x^2\right )^{7/2}} \]

Antiderivative was successfully verified.

[In]

Integrate[1/(x*(b*x^2)^(5/2)),x]

[Out]

-1/5*(b*x^2)/(b*x^2)^(7/2)

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fricas [A]  time = 0.65, size = 15, normalized size = 0.79 \[ -\frac {\sqrt {b x^{2}}}{5 \, b^{3} x^{6}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x/(b*x^2)^(5/2),x, algorithm="fricas")

[Out]

-1/5*sqrt(b*x^2)/(b^3*x^6)

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giac [A]  time = 0.15, size = 15, normalized size = 0.79 \[ -\frac {1}{5 \, \sqrt {b x^{2}} b^{2} x^{4}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x/(b*x^2)^(5/2),x, algorithm="giac")

[Out]

-1/5/(sqrt(b*x^2)*b^2*x^4)

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maple [A]  time = 0.00, size = 10, normalized size = 0.53 \[ -\frac {1}{5 \left (b \,x^{2}\right )^{\frac {5}{2}}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/x/(b*x^2)^(5/2),x)

[Out]

-1/5/(b*x^2)^(5/2)

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maxima [A]  time = 1.36, size = 8, normalized size = 0.42 \[ -\frac {1}{5 \, b^{\frac {5}{2}} x^{5}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x/(b*x^2)^(5/2),x, algorithm="maxima")

[Out]

-1/5/(b^(5/2)*x^5)

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mupad [B]  time = 0.92, size = 10, normalized size = 0.53 \[ -\frac {1}{5\,b^{5/2}\,{\left (x^2\right )}^{5/2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(x*(b*x^2)^(5/2)),x)

[Out]

-1/(5*b^(5/2)*(x^2)^(5/2))

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sympy [A]  time = 1.03, size = 15, normalized size = 0.79 \[ - \frac {1}{5 b^{\frac {5}{2}} \left (x^{2}\right )^{\frac {5}{2}}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x/(b*x**2)**(5/2),x)

[Out]

-1/(5*b**(5/2)*(x**2)**(5/2))

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